tag:blogger.com,1999:blog-7917895945267682444.post3960901357714922991..comments2023-08-27T03:16:41.315-07:00Comments on Los retos matemáticos del mes: Reto 41: ¡A contar!Unknownnoreply@blogger.comBlogger5125tag:blogger.com,1999:blog-7917895945267682444.post-37273347312016137042013-01-05T22:44:10.459-08:002013-01-05T22:44:10.459-08:00A=7
B=6.5
C=6.5
D=6.5
E=4
A=7, B=C=D, E=4//A=7<br />B=6.5<br />C=6.5<br />D=6.5<br />E=4<br /><br />A=7, B=C=D, E=4//edgar martin p.https://www.blogger.com/profile/12615206663552377867noreply@blogger.comtag:blogger.com,1999:blog-7917895945267682444.post-50340083338131966912013-01-05T22:41:20.155-08:002013-01-05T22:41:20.155-08:00Este comentario ha sido eliminado por el autor.edgar martin p.https://www.blogger.com/profile/12615206663552377867noreply@blogger.comtag:blogger.com,1999:blog-7917895945267682444.post-4395698144845349052013-01-05T22:37:16.807-08:002013-01-05T22:37:16.807-08:00Este comentario ha sido eliminado por el autor.edgar martin p.https://www.blogger.com/profile/12615206663552377867noreply@blogger.comtag:blogger.com,1999:blog-7917895945267682444.post-48739270644223039362012-12-30T09:34:46.327-08:002012-12-30T09:34:46.327-08:00SOLUCIÓN CON EXPLICACIÓN ABAJO.
---------------...SOLUCIÓN CON EXPLICACIÓN ABAJO.<br /><br /><br /><br />----------------------------------------<br /><br /><br /><br /><br /><br />La unidad más básica de todas es el cuadrado (C). 2C=círculo (O), y, a su vez, Rombo (R)= 3O = 6C. Una vez tenemos estos datos, podemos sustituir en cada conjunto por el valor más pequeño de todos: C.<br />En A: 3O+2C+R = 6C+2C+6C = 14C<br />En B: R+C+R = 6C+C+6C = 13C<br />En C: C+6O = C+12C = 13C<br />En D: 3C+R+2O = 3C+6C+4C = 13C<br />En E: 2C+2O+2C = 2C+4O+2C = 8C<br /><br />Por tanto, la solución serían B=C=D= 13 Cuadrados.<br />¡Un saludo!Alejohttps://www.blogger.com/profile/00863687446106024210noreply@blogger.comtag:blogger.com,1999:blog-7917895945267682444.post-10800625724525686102012-10-25T10:41:23.357-07:002012-10-25T10:41:23.357-07:00C y B.C y B.Inés Villamor Noreshttps://www.blogger.com/profile/16376123272941924508noreply@blogger.com